dim caizhi1 as string dim caizhi2 as string dim caizhi as string dim dianzulv1 as double dim dianzulv2 as double dim midu1 as double dim midu2 as double dim zhijing as double dim jiejubi as double dim jiemianji as double dim zhouchang as double dim dianzusichangdu as double dim zhongliang as double dim quanshu as double dim jieju as double dim dianzulv as double dim midu as double dim zuzhi as double private sub command1_click() dim xlapp as object dim xlworkbook as object dim xlworkshee
请问您是希望对这段代码进行解释、修改完善，还是基于它为您生成新的代码段呢？或者还有其他的具体需求？ [2024-10-31 15:19:51 | AI写代码神器 | 32点数解答]
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- dim caizhi1 as string dim caizhi2 as string dim caizhi as string dim dianzulv1 as double dim dianzulv2 as double dim midu1 as double dim midu2 as double dim zhijing as double dim jiejubi as double dim jiemianji as double dim zhouchang as double dim dianzusichangdu as double dim zhongliang as double dim quanshu as double dim jieju as double dim dianzulv as double dim midu as double dim zuzhi as double private sub command1_click() dim xlapp as object dim xlworkbook as object dim xlworkshee（32点数解答 | 2024-10-31 15:19:51）191
- private sub commandbutton3_click() dim ws as worksheet dim rng as range dim cell as range dim combinedarray() as string dim i as long dim j as long dim k as long dim isduplicate as boolean ' 设置工作表对象 set ws = thisworkbook.worksheets("行—原始数据") ' 初始化数组 redim combinedarray(1 to ws.cells(ws.rows.count, "d").end(xlup).row) ' 遍历a列、b列和c列的所有单元格 i = 1 do while not isempty(ws.cells(i, "d")) ' 合并b列和c列的相应单元格 combinedarray(i) = ws.（158点数解答 | 2024-12-26 15:05:50）129
- Sub DeleteFilesInFolder() Dim folderPath As String Dim fileName As String Dim i As Long Dim lastRow As Long Dim ws As Worksheet Set ws = ThisWorkbook.Sheets("Sheet1") '设文件名列表在Sheet1的A列 folderPath = "D:\600单元试压包\06" '换为文件夹路径 lastRow = ws.Cells(ws.Rows.Count, "A").End(xlUp).Row For i = 2 To lastRow fileName = ws.Cells(i, 1).Value If fileName <> "" Then Kill folderPath & fileName End If Next i End Sub（238点数解答 | 2025-01-14 15:03:16）155
- // rod6.cpp : defines the entry point for the console application. // #include "stdafx.h" // consoleapplication2.cpp : 此文件包含 "main" 函数。程序执行将在此处开始并结束。 // #include <stdio.h> #include <math.h> #include <iostream> #include <conio.h> #include <cstdlib> using namespace std; double ro[10001]; double th[10001]; double e[10001]; double a[10001]; double b[10001]; double y[10001]; double x[10001]; double d[10001]; double d[10001]; double da[10001]; double db[10001]; double dc[10001]; double z[10001]; d（55点数解答 | 2024-08-16 15:22:27）204
- ```csharp using system; interface igetmoney { double callfee(int minutes); } class acard : igetmoney { private const double initialfee =100; private const double feeperminute = 0.1; private const int freeminutes = 3; private double balance; public acard() { balance = initialfee; } public double callfee(int minutes) { double fee = 0; if (minutes <= freeminutes) { fee = 0; } else { fee = (minutes - freeminutes) * feeperminute; } balance -= fee; return fee; } public double getbalance() { re（291点数解答 | 2024-05-27 16:22:31）239
- #define _crt_secure_no_warnings #include <iostream> #include <cstdlib> #include <cmath> #include <vector> #include <cstdio> using namespace std; // 你的代码... const int nx = 784, nb = 500, ny = 10;//输入层x，隐藏层b，输出层y节点数 const double eta = 0.1;//学习率 struct node { double val{}; double bias{}; vector<double> weight; } x[nx], b[nb], y[ny];//输入层x，隐藏层b，输出层y double g[ny], e[nb];//用于反向传播 double trainx[nx], trainy[ny];//训练数据 double sigmoid(double x) { return 1.0 / (1.0 + exp(-x)); } double（34点数解答 | 2024-09-06 08:43:52）256
- #define _crt_secure_no_warnings #include <iostream> #include <cstdlib> #include <cmath> #include <vector> #include <cstdio> using namespace std; // 你的代码... const int nx = 784, nb = 500, ny = 10;//输入层x，隐藏层b，输出层y节点数 const double eta = 0.1;//学习率 struct node { double val{}; double bias{}; vector<double> weight; } x[nx], b[nb], y[ny];//输入层x，隐藏层b，输出层y double g[ny], e[nb];//用于反向传播 double trainx[nx], trainy[ny];//训练数据 double sigmoid(double x) { return 1.0 / (1.0 + exp(-x)); } double（1309点数解答 | 2024-09-06 08:46:09）267
- #include <stdio.h> #include <math.h> #define pi 3.14159265358979323846 double meridianarclength(double b) { double a = 6378140.0; double e2 = 0.00669438002290; double m = a * (1 - e2) * (1 - e2 * sin(b) * sin(b)) * pow(1 - e2 * sin(b) * sin(b), 1.5); double n = a / sqrt(1 - e2 * sin(b) * sin(b)); return m + n * sin(b) * cos(b) * pow(tan(b),2) /2 + n * sin(b) * pow(cos(b), 3) * (5 - pow(tan(b), 2) + 9 * e2 * pow(cos(b), 2)) * pow(tan(b), 4) / 24; } double calculatebaselatitude(double x, double y)（565点数解答 | 2024-11-21 13:08:38）153
- #include <stdio.h> #include <math.h> #define pi 3.14159265358979323846 double meridianarclength(double b) { double a = 6378140.0; double e2 = 0.00669438002290; double m = a * (1 - e2) * (1 - e2 * sin(b) * sin(b)) * pow(1 - e2 * sin(b) * sin(b), 1.5); double n = a / sqrt(1 - e2 * sin(b) * sin(b)); return m + n * sin(b) * cos(b) * pow(tan(b),2) /2 + n * sin(b) * pow(cos(b), 3) * (5 - pow(tan(b), 2) + 9 * e2 * pow(cos(b), 2)) * pow(tan(b), 4) / 24; } double calculatebaselatitude(double x,（48点数解答 | 2024-11-21 13:05:21）144
- private int toagentid; /* 关联代理商id */ private int money; /* 增加数量 */ private int operateid; /* 操作系统账号id，对应t_sys_user表id */ private date createtime;/* 操作时间 */ private string info; /* 信息 */ private int type; /* 0后台修改代理钻石；1开房返还钻石记录 */，实体类语言为：Java，数据库类型：Mysql数据库 （212点数解答 | 2024-12-24 10:11:54）172
- public static void main(string[] args) { string imgpath = "d:\ruoyi\uploadpath\upload\shuyoubi\20240726192938460.jpg"; double rate = imagecompareutils.compareimage(imgpath); double focallength = 4; // 焦距，单位：毫米 double actualsize = 9.6; // 物体实际尺寸，单位：厘米 double pixelsize = 298.8999938964844*2; // 物体在图片中的像素尺寸 double distance = calculatedistance(focallength, actualsize, pixelsize); system.out.println("物体与相机之间的距离为： " + distance + " 厘米"); system.out.println("偏移量：" + rate); // double（253点数解答 | 2024-07-27 09:18:40）179
- #include<stdio.h> int main() { double r, h; //定义变量r（半径）和h（高度） const double pi = 3.1415926; //定义常量pi // 输入半径r和高度h printf("请输入圆的半径 r 和圆柱的高 h (例如: 5 10): "); scanf("%lf %lf", &r, &h); // 计算各项值 double circumference = 2 * pi * r; //圆的周长 double circle_area = pi * r * r; // 圆的面积 double sphere_surface_area = 4 * pi * r * r; // 圆球的表面积 double sphere_volume = (4.0 / 3) * pi * r * r * r; //圆球的体积 double cylinder_volume = circle_area * h; // 圆柱的体积 // 输出结果，保留两位小数 printf("圆的周长: %.2f\n", circumference); prin（668点数解答 | 2024-10-19 10:58:06）173