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#define _crt_secure_no_warnings #include <stdio.h> #include <stdlib.h> int isperfectnum(int number) { int* arr = (int*)malloc(number * sizeof(int)); if (arr == null) { // 处理内存分配失败的情况 return false; } int res; int sum = 0; int n = 0; for (int q = 1; q < number; q++) { res = number % q; if (res == 0) { arr[n] = q; n++; } } for (n = 0; n < number - 1; n++) { sum += arr[n];
您提供的这段代码存在一些问题。首先，在 C 语言中，判断指针是否为空应该使用 `NULL` 而不是 `null` 。在最后的求和循环中，没有考虑到数组可能没有填满整个分配的空间。以下是修正后的代码： ```c #include <stdio.h> #include <stdlib.h> int isperfectnum(int number) { int* arr = (int*)malloc(number * sizeof(int)); if (arr == NULL) { // 处理内存分配失败的情况 printf("内存分配失败！\n"); return 0; } int res; int sum = 0; int n = 0; for (int q = 1; q < number; q++) { res = number % q; if (res == 0) { arr[n] = q; n++; } } for (int i = 0; i < n; i++) // 这里修改为 i < n ，只遍历实际存储了因数的部分 { sum += arr[i]; } free(arr); // 记得释放分配的内存 if (sum == number) { return 1; } else { return 0; } } int main() { int num = 6; if (isperfectnum(num)) { printf("%d 是完美数\n", num); } else { printf("%d 不是完美数\n", num); } return 0; } ``` [2024-10-31 22:35:11 | AI写代码神器 | 391点数解答]
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