#include <stc15f2k60s2.h> // 数码管段选码 unsigned char code seg_code[] = { 0xc0, 0xf9, 0xa4, 0xb0, 0x99, 0x92, 0x82, 0xf8, 0x80, 0x90, 0x88, 0x83, 0xc6, 0xa1, 0x86, 0x8e }; // 数码管位选码 unsigned char code bit_code[] = { 0xfe, 0xfd, 0xfb, 0xf7, 0xef, 0xdf, 0xbf, 0x7f }; void delay(unsigned int t) { while (t--) ; } void initadc() { p1asf = 0xff; // 将 p1 口设置为模拟输入口 adc_contr = 0x80; // 打开 adc 电源 delay(2); // 适当延时等待 adc 电源稳定 } unsigned int getadcresult() { adc_con


It looks like you're working on a project involving an STC15F2K60S2 microcontroller, specifically for controlling a 7-segment display and possibly reading from an ADC (Analog-to-Digital Converter). However, the code provided is incomplete. I'll help you complete it by filling in the missing parts and providing some context. Here's a more complete version of your code: ```c #include <stc15f2k60s2.h> // 数码管段选码 unsigned char code seg_code[] = { 0xc0, 0xf9, 0xa4, 0xb0, 0x99, 0x92, 0x82, 0xf8, 0x80, 0x90, 0x88, 0x83, 0xc6, 0xa1, 0x86, 0x8e }; // 数码管位选码 unsigned char code bit_code[] = { 0xfe, 0xfd, 0xfb, 0xf7, 0xef, 0xdf, 0xbf, 0x7f }; void delay(unsigned int t) { while (t--); } void initADC() { P1ASF = 0xff; // 将 P1 口设置为模拟输入口 ADC_CONTR = 0x80; // 打开 ADC 电源 delay(2); // 适当延时等待 ADC 电源稳定 } unsigned int getADCResult() { ADC_CONTR = ADC_CONTR | 0x08; // 启动 ADC 转换 while (!(ADC_CONTR & 0x10)); // 等待转换完成 ADC_CONTR &= ~0x10; // 清除转换完成标志 return (ADC_RES << 2) | (ADC_RESL >> 6); // 返回 ADC 结果 } void displayDigit(unsigned char position, unsigned char value) { P2 = bit_code[position]; // 选择数码管位置 P0 = seg_code[value]; // 显示数字 delay(500); // 短暂延时以保持显示 P0 = 0xff; // 关闭显示 } void main() { initADC(); // 初始化 ADC while (1) { unsigned int adcValue = getADCResult(); // 获取 ADC 值 displayDigit(0, adcValue % 10); // 显示个位数 displayDigit(1, adcValue / 10 % 10); // 显示十位数 displayDigit(2, adcValue / 100 % 10); // 显示百位数 displayDigit(3, adcValue / 1000 % 10); // 显示千位数 } } ``` Explanation: 1. Initialization: The `initADC` function initializes the ADC by setting the appropriate registers. 2. Reading ADC: The `getADCResult` function starts the ADC conversion and waits for it to complete before returning the result. 3. Display Function: The `displayDigit` function controls which segment of the display is active and what value is shown. 4. Main Loop: In the `main` function, the program continuously reads the ADC value and displays it on the 7-segment display. Notes: - Ensure that the hardware connections are correct and that the necessary peripherals are properly configured. - The delay values might need adjustment based on your specific requirements and clock speed. - This example assumes a basic understanding of how the STC15F2K60S2 works with its peripherals. You may need to refer to the datasheet for more details. [2024-11-07 17:31:31 | AI写代码神器 | 939点数解答]
- #include <stc15f2k60s2.h> // 数码管段选码 unsigned char code seg_code[] = { 0xc0, 0xf9, 0xa4, 0xb0, 0x99, 0x92, 0x82, 0xf8, 0x80, 0x90, 0x88, 0x83, 0xc6, 0xa1, 0x86, 0x8e }; // 数码管位选码 unsigned char code bit_code[] = { 0xfe, 0xfd, 0xfb, 0xf7, 0xef, 0xdf, 0xbf, 0x7f }; void delay(unsigned int t) { while (t--) ; } void initadc() { p1asf = 0xff; // 将 p1 口设置为模拟输入口 adc_contr = 0x80; // 打开 adc 电源 delay(2); // 适当延时等待 adc 电源稳定 } unsigned int getadcresult() { adc_con(939点数解答 | 2024-11-07 17:31:31)169
- 51单片机实现电子时钟,共阴极uchar code dis_code[] = {0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8, 0x80, 0x90,0x88,0xC0,};引脚。在数码管上显示的格式为小时-分钟-秒(571点数解答 | 2025-04-22 14:01:21)87
- #include<iostream> #include<complex.h> #include <complex> #include <math.h> using namespace std; #define pi 3.14159265358979323846 int main() { file* stream; stream = fopen("4000-red.raw","rb"); unsigned char* image = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); fread(image,4000*4000,sizeof(unsigned char),stream); unsigned char* image2 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); unsigned char* image3 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned(413点数解答 | 2024-11-02 18:16:35)192
- 采用c++语言,实现如下功能: 实现古典密码中的移位密码和仿射密码,具体实现如下接口: c++接口: <<<<<移位密码>>>>> bool is_valid_s(unsinged char k) { 判断k是否为合理的密钥 } int encrypt_s(unsigned char* p, unsigned char k) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_s(unsigned char* c, unsigned char k) { 密钥合法则返回1,且明文覆盖密文: 密钥不合法则返回0. } <<<<<仿射密码>>>>> bool in_valid_a(unsinged char a, unsigned char b) { 判断a,b是否为合理的密钥 } int encrypt_a(unsigned char* p, unsigned char a, unsigned char b) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_a(unsigned char* c, unsign(812点数解答 | 2024-12-18 16:02:36)228
- 把这个代码修改正确#include<reg52.h> sbit key = p3^0; // 按键连接到p3.0 unsigned char code seg_code[] = {0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f}; // 数码管段码 unsigned char code dash_code = 0x40; // 横杠段码 unsigned int second =0; // 秒表计数 bit running = 0; // 秒表运行状态 void timer0_isr() interrupt 1 { static unsigned int count =0; th0 = (65536 - 1000) / 256; tl0 = (65536 - 1000) %256; count++; if (count >= 1000) { count = 0; if (running) { second++; } } } void delay(unsigned int ms) { unsigned int i(776点数解答 | 2024-10-23 22:51:51)188
- 完善代码#include<reg51.h> #include <intrins.h> code unsigned char tab[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40}; unsigned char dspbuf[8] = {0,0,10,0,0,10,0,0}; unsigned char i,j,k; unsigned char dspbuf1[8] = {0,0,10,0,0,10,0,0}; code unsigned int yindiao[]={0,120,106,94,89,79,71,62,59, 56, 53, 50, 47, 44, 41, 38}; code unsigned int jiepai[]={0,523,587,659,698,784,880,988};(334点数解答 | 2024-11-25 18:12:57)148
- 告诉我那里错误#include<reg51.h> #include <intrins.h> code unsigned char tab[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40}; unsigned char dspbuf[8] = {0,0,10,0,0,10,0,0}; unsigned char i,j,k; unsigned char dspbuf1[8] = {0,0,10,0,0,10,0,0}; code unsigned int yindiao[]={0,120,106,94,89,79,71,62,59, 56, 53, 50, 47, 44, 41, 38}; code unsigned int jiepai[]={0,523,587,659,698,784,880,988(78点数解答 | 2024-11-25 18:13:58)149
- #include <reg51.h> sbit LED = P1^0; sbit KEY = P1^1; void delay(unsigned int ms) { unsigned int i; for(; ms>0; ms--) for(i=0; i<120; i++); } void main() { while(1) { if(KEY == 0) { delay(20); if(KEY == 0) { LED = ~LED; while(KEY == 0); } } } } (326点数解答 | 2025-06-22 23:19:40)77
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(710点数解答 | 2024-11-14 10:44:25)205
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(951点数解答 | 2024-11-14 10:46:29)200
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(472点数解答 | 2024-11-14 10:51:44)180
- int n = 3; int width1 = width * n; int height1 = height * n; unsigned char* image9 = (unsigned char*)malloc(sizeof(unsigned char) * width1*height1); for (int i = 0; i < height1; i++) { for (int j = 0; j < width1; j++) { int a = i /n; int b = j /n; image9[i * width1 + j] = image1[a * width + b ]; } } char result6[100] = "suofang.raw"; file* fp6 = fopen(result6, "wb"); fwrite(image9, sizeof(unsigned cha(348点数解答 | 2024-10-26 12:13:04)206