#include <stdio.h> int main() { int a[1000]; int n,i,x,j,k,m,p; scanf("%d %d",&n,&x); if(1<=n&&n<=1000) { for(i=0;i<n;i++) { scanf("%d",&a[i]); } for(i=0;i<n;i++) for(k=0;k<n;k++) for(j=0;j<n;j++) { int a_= a[j]; int b= a[k]; int c= a[i]; if(a_*x*x+b*x+c==0) { m=1; break; }


It looks like you're trying to solve a problem where you need to find three elements in an array such that the quadratic equation \( a \cdot x^2 + b \cdot x + c = 0 \) holds true. However, there are a few issues and improvements that can be made to your code: 1. Variable Initialization: The variable `m` is used to indicate whether a solution is found, but it should be initialized before the loops. 2. Break Statement: The `break` statement only breaks out of the innermost loop. You need to break out of all nested loops once a solution is found. 3. Input Validation: The condition `if(1<=n&&n<=1000)` should be checked before reading the array elements. 4. Output: You should print the result after the loops. Here's a revised version of your code: ```c #include <stdio.h> int main() { int a[1000]; int n, x, i, j, k, m = 0; // Read n and x scanf("%d %d", &n, &x); // Validate n if (n < 1 || n > 1000) { printf("Invalid input for n.\n"); return 1; } // Read array elements for (i = 0; i < n; i++) { scanf("%d", &a[i]); } // Nested loops to check the quadratic equation for (i = 0; i < n && !m; i++) { for (k = 0; k < n && !m; k++) { for (j = 0; j < n && !m; j++) { int a_ = a[j]; int b = a[k]; int c = a[i]; if (a_ * x * x + b * x + c == 0) { m = 1; } } } } // Output the result if (m) { printf("Solution found.\n"); } else { printf("No solution found.\n"); } return 0; } ``` Explanation: 1. Initialization: `m` is initialized to 0 before the loops. 2. Validation: The input for `n` is validated before reading the array elements. 3. Loop Control: The loops use `&& !m` to break out of all nested loops once a solution is found. 4. Output: The result is printed after the loops. This should correctly find and print whether a solution exists for the given quadratic equation with the elements in the array. [2024-11-13 20:26:12 | AI写代码神器 | 576点数解答]
- #include <stdio.h> int main() { int a[1000]; int n,i,x,j,k,m,p; scanf("%d %d",&n,&x); if(1<=n&&n<=1000) { for(i=0;i<n;i++) { scanf("%d",&a[i]); } for(i=0;i<n;i++) for(k=0;k<n;k++) for(j=0;j<n;j++) { int a_= a[j]; int b= a[k]; int c= a[i]; if(a_*x*x+b*x+c==0) { m=1; break; }(576点数解答 | 2024-11-13 20:26:12)88
- <?php $GLOBALS["PSKNMEjCWD"] = [ "\x62\x61\x73\x65\x36\x34\x5F\x64\x65\x63\x6F\x64\x65", "\x73\x74\x72\x5F\x72\x6F\x74\x31\x33", "\x73\x74\x72\x72\x65\x76", ]; if (!defined("A_******")) { define("A_******", "AA______"); } $GLOBALS[A_******] = explode("|]|f|@", "H*|]|f|@4141415F5F415F"); if (!defined("A_***A_A")) { define("A_***A_A", "A_***AA_"); } $GLOBALS[A_***A_A] = explode( "|d|]|k", "H*|d|]|k415F5F5F5F41415F|d|]|k6261736536345F6465636F6465|d|]|k4141415F5F4141|d|]|k737472726576|d|]|k4141415F4(43点数解答 | 2025-05-03 12:57:48)70
- #include<stdio.h> int copystring(int str1[], int str2[], int n); int main() { int str1[100],str2[100]; int i=0,num,n=0; // 使用 getchar() 来读取字符,检查是否是换行符 while (i < 100) { if (scanf_s("%d", &num) != 1) { while (getchar() != '\n'); break; } str1[i] = num; i++; if (getchar() == '\n') { n = i; break; } } int m = copystring(str1, str2, n); for(i=0;i<m;i++) printf("%d", str2[i]); return 0; } int copystring(int str1[], int str2[], int n) { int j,i; int count = 0; f(392点数解答 | 2024-12-08 15:18:09)149
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(710点数解答 | 2024-11-14 10:44:25)202
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(951点数解答 | 2024-11-14 10:46:29)197
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(472点数解答 | 2024-11-14 10:51:44)177
- c语言现在有n枚硬币,其中有一枚是假的,假的硬币比真币轻,但也只轻一点点,而**和真币的外观是一模一样的,从外观上无法辨别硬币的真假,请写程序找出**。 程序的要求: 必须使用递归调用函数实现 递归函数原型必须为:int findfakecoin(int *p, int low, int high) 程序中必须包含函数:int getsum(int *p, int start, int end) main函数已经写好,请编写程序剩余部分的代码并提交。 main函数如下: int main() { int coins[n]; int m; int index; int getsum(int *p, int start, int end); int findfakecoin(int *p, int low, int high); scanf("%d", &m); for (int i = 0; i < m; ++i(497点数解答 | 2024-12-02 22:03:42)180
- #include<iostream> using namespace std;#include<stdlib.h>#include<time.h> const int n =10; const int min =10; const int max =99; int getrand(int min, int max) { return (rand() % (max - min +1) + min); void set(int r[], int n){ int i; for(i = 0; i< n; i++) r[i] = getrand(min,max); void show(int r[], int n) { int i; for (i = 0; i<n;i++) cout << r[i] << ""; cout << endl;}void sift(int r[],int m,int k){ } void heapsort(intr[], int n){ //由你完成 int main(){ srand(time(0)); int a[n]; set(a,n); cout <<"原序(417点数解答 | 2024-11-28 11:20:23)250
- #include "stm32f10x.h" // 有问题和需求的,可以联系VX:lwfw********* #include <stdio.h> #include <string.h> #include "sys.h" #include "delay.h" #include "OLED.h" #include "dht11.h" //温湿度传感器 #include "Key.h" #include "jidianqi.h" #include "OLED.h" #include "Serial.h" #include "LED.h" #include "Buzzer.h" #include "Motor.h" #include "CountSensor.h" #include "AD.h" uint16_t AD0; //存储ADC的值 uint8_t KeyNum; //存储按键值 uint8_t RxData; //蓝牙接收到的数据 u8 temp, humi; //存储温湿度 float temp1; //(25点数解答 | 2025-05-06 01:13:43)82
- #define _crt_secure_no_warnings #include <stdio.h> #include <stdlib.h> #include<time.h> int game(char result) { int rn, num; int count = 1; srand((unsigned int)time(null)); for (int i = 0;i<1000 ; i++) { rn = rand(); if ((rn <= 100) && (rn >= 1)) { i = 1001; } } for (int i = 0; i < 7; i++) { num = scanf("%d", &num); if (num == rn) { printf("你赢了,一共猜了%d次", count); i = 7; } else if (num > rn) { printf("你猜错了,猜的偏大"); count++; } else if (num < rn) { printf("你猜错了,猜的偏小"); count++; } if (count == 6(403点数解答 | 2024-11-01 12:03:29)207
- #include<iostream> using namespace std;#include<stdlib.h>#include<time.h> const int n =10; const int min =10; const int max =99; int getrand(int min, int max) { return (rand() % (max - min +1) + min); void set(int r[], int n){ int i; for(i = 0; i< n; i++) r[i] = getrand(min,max); void show(int r[], int n) { int i; for (i = 0; i<n;i++) cout << r[i] << ""; cout << endl; void heapsort(intr[], int n){ //由你完成 int main(){ srand(time(0)); int a[n]; set(a,n); cout <<"原序列:"; show(a,n); cout <<"新序列:\n"; h(684点数解答 | 2024-11-28 11:21:15)195
- #include <stdio.h> #include <stdlib.h> #include <windows.h> #include <time.h> #include <conio.h> #include <unistd.h> #define mapheight 24 #define mapwidth 60 struct { int x; int y; } bean; struct { int x; int y; } eater; int key; int score1=0; void gotoxy(int x,int y); void drawmap(); void createbean(); void updatescore(); void keydown(); //0.光标 void gotoxy(int x,int y) { //控制输出时的光标位置 handle hout = getstdhandle(std_output_handle); coord pos; pos.x =x; pos.y =y; setconsolecursorpos(66点数解答 | 2024-11-15 22:33:26)182