def is_valid_position(n, m, x, y):
if x <0 or x >= n or y < 0 or y >= m:
return false
return true
def dfs(n, m, x, y, visited):
directions = [(1, 2), (1, -2), (-1, 2), (-1, -2), (2,1), (2, -1), (-2, 1), (-2, -1)]
visited[x][y] = true
count = 0
for dx, dy in directions:
new_x, new_y = x + dx, y + dy
if is_valid_position(n, m, new_x, new_y) and not visited[new_x][new_y]:
count += dfs(n, m, new_x, new_y, visited)
visited[x][y] = false
if count == 0:
return1 if all(visited[i][j] for i in range(n) f
or j in range(m) else 0
If there is a tour, it will return 1, otherwise 0.
[2024-11-18 19:36:52 | AI写代码神器 | 50点数解答]