以下是使用 Python 解决此问题的代码： ```python input_data = [ "CN0010 DF0001", "BF0001 AZ0001", "AZ0001 NA", "DF0010 AZ0001", "AW0001 NA", "BF0011 AZB001" ] # 将输入数据转换为一个列表，每个元素是一个版本号字符串 versions = [] for item in input_data: versions.extend(item.split()) # 统计每个版本号出现的次数 counts = {} for version in versions: if version in counts: counts[version] += 1 else: counts[version] = 1 # 找到出现次数最多的次数 max_count = max(counts.values()) # 筛选出出现次数最多的版本号 most_frequent_versions = [version for version, count in counts.items() if count == max_count] # 对版本号进行升序排序 most_frequent_versions.sort() # 以空格隔开输出 print(" ".join(most_frequent_versions)) ``` [2025-04-09 19:21:47 | AI问答 | 273点数解答]