好的，我明白了。根据您提供的要求，我将生成一组模拟数据，并使用Python进行各科成绩统计值的计算。下面是我的代码： ```python import numpy as np # 生成学生数据 students = [['2023101', 96, 62, 87], ['2023102', 90, 96, 60], ['2023103', 73, 89, 91], ['2023104', 77, 70, 62], ['2023105', 93, 91, 80]] # 生成学生数量 n = int(input("请输入学生数量：")) # 初始化各科成绩统计值 chinese_avg = np.zeros(n) chinese_std = np.zeros(n) chinese_median = np.zeros(n) math_avg = np.zeros(n) math_std = np.zeros(n) english_avg = np.zeros(n) english_std = np.zeros(n) # 计算各科成绩统计值 for i in range(n): chinese_avg[i] = np.mean([student[1] for student in students[i*4:]]) chinese_std[i] = np.std([student[1] for student in students[i*4:]]) chinese_median[i] = np.median([student[1] for student in students[i*4:]]) math_avg[i] = np.mean([student[2] for student in students[i*4 + 1:]]) math_std[i] = np.std([student[2] for student in students[i*4 + 1:]]) english_avg[i] = np.mean([student[3] for student in students[i*4 + 2:]]) english_std[i] = np.std([student[3] for student in students[i*4 + 2:]]) print("各科成绩统计值如下：") print("语文平均分：", round(chinese_avg, 2)) print("数学平均分：", round(math_avg, 2)) print("外语平均分：", round(english_avg, 2)) print("语文标准差：", round(chinese_std, 2)) print("数学标准差：", round(math_std, 2)) print("外语标准差：", round(english_std, 2)) print("语文中位数：", round(chinese_median, 2)) ``` 这段代码将首先从模拟数据中获取学生信息，然后根据学生的数量n进行循环计算各科成绩的平均分、标准差和中位数，并输出结果。这段代码假设学生的学号是从'2023101'开始顺序编号的。如果您的实际数据与此不符，请相应地修改代码。 [2024-05-08 11:24:39 | AI写代码神器 | 699点数解答]