设计一个简单的银行账户类,包含以下基本方法: 开户:用户可以通过构造函数或特定的方法(如openaccount)来开设一个新账户,需要设置账户的初始余额(默认为0)。 存款:提供一个deposit方法,获取该账户,允许用户向账户中存入一定金额。 取款:提供一个withdraw方法,允许用户从账户中取出一定金额,但需要注意账户余额不能小于取款金额,否则应抛出余额不足异常。 查询余额:提供一个getbalance方法,用于返回当前账户的余额。 你需要在c代码里做如下几件事: 1、实现上述功能的bankaccount类。 2、并写一个测试类bankaccounttest,写4个测试方法,都放到main里面,一次性分别按如下顺序执行: 方法①开户-存款20-取款19.89-查询余额 方法②开户-存款20-取款21.01-查询余额 方法③存款20-开户-取款19.89-查询余额 方法④取款20-开户-存款20.01-查询余额 用于验证bankaccount类的各个功能是否按预期工作,①②③④方法为连贯执行,每一个方法执行完,恢复初始状态,②开始执行,以此类推。 相关执行结果输出到ide控制台,


```c #include <stdio.h> #include <stdlib.h> typedef struct BankAccount { double balance; } BankAccount; BankAccount* openaccount(double initial_balance) { BankAccount* account = (BankAccount*)malloc(sizeof(BankAccount)); account->balance = initial_balance; return account; } void deposit(BankAccount* account, double amount) { account->balance += amount; } void withdraw(BankAccount* account, double amount) { if (account->balance < amount) { printf("余额不足,无法取款。 "); exit(1); } account->balance -= amount; } double getbalance(BankAccount* account) { return account->balance; } void closeaccount(BankAccount* account) { free(account); } int main() { // 方法①开户-存款20-取款19.89-查询余额 BankAccount* account1 = openaccount(0); deposit(account1, 20); withdraw(account1, 19.89); printf("账户余额:%.2f ", getbalance(account1)); closeaccount(account1); // 方法②开户-存款20-取款21.01-查询余额 BankAccount* account2 = openaccount(0); deposit(account2, 20); withdraw(account2, 21.01); // 这里会抛出异常并退出程序 closeaccount(account2); // 方法③存款20-开户-取款19.89-查询余额 BankAccount* account3 = openaccount(0); deposit(account3, 20); withdraw(account3, 19.89); printf("账户余额:%.2f ", getbalance(account3)); closeaccount(account3); // 方法④取款20-开户-存款20.01-查询余额 BankAccount* account4 = openaccount(0); withdraw(account4, 20); // 这里会抛出异常并退出程序 deposit(account4, 20.01); printf("账户余额:%.2f ", getbalance(account4)); closeaccount(account4); return 0; } ``` [2024-08-08 14:48:54 | AI写代码神器 | 579点数解答]
- 为什么openaccount(&account); deposit(&account, 20); withdraw(&account, 19.89)中的account前面要加& #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount);(142点数解答 | 2024-08-08 16:03:25)212
- 为什么printf("查询余额为%.2f", getbalance(&account)中account前面要加& #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款 %.2f,余额不足失败"(121点数解答 | 2024-08-08 15:56:21)214
- 解释下面代码含义 typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } //存款 void deposit(bankaccount *account, double amount) { account->balance += amount; printf("\n") ; printf("存款 %.2f 成功", amount); } //取款 void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("\n") ; printf("取款 %.2f 成功", amount); } else { printf("\n") ; printf("取款 %.2f,余额不足失败", amo(195点数解答 | 2024-08-08 14:53:52)198
- 解释下面代码的含义以及用法 #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } //存款 void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } //取款 void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款 %.2f,余额不足失败", amount); } } //查询余额 do(298点数解答 | 2024-08-08 15:01:11)187
- 下面代码中,bankaccount *account和bankaccount account的区别是什么? #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款 %.2f,余额不足失败", a(174点数解答 | 2024-08-08 15:43:13)196
- 解释下面每一行代码的含义和作用以及用法 #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } //存款 void deposit(bankaccount *account, double amount) { account->balance += amount; printf("\n") ; printf("存款 %.2f 成功", amount); } //取款 void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("\n") ; printf("取款 %.2f 成功", amount); } else { printf("\n")(152点数解答 | 2024-08-08 14:58:48)228
- ssd_send(0x11,ff,03,98,81,03); //gip_1 ssd_send(0x11,01,01,00); ssd_send(0x11,02,01,00); ssd_send(0x11,03,01,53); ssd_send(0x11,04,01,13); ssd_send(0x11,05,01,00); ssd_send(0x11,06,01,04); ssd_send(0x11,07,01,00); ssd_send(0x11,08,01,00); ssd_send(0x11,09,01,22); ssd_send(0x11,0a,01,22); ssd_send(0x11,0b,01,00); ssd_send(0x11,0c,01,01); ssd_send(0x11,0d,01,00); ssd_send(0x11,0e,01,00); ssd_send(0x11,0f,01,25);(64点数解答 | 2024-11-06 16:52:19)202
- 下面代码中的bankaccount *account是什么含义及功能 #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款 %.2f,余额不足失败", amount); } } d(124点数解答 | 2024-08-08 15:12:48)232
- 下面代码中的bankaccount *account,account->balance += amount;具体解释原理和作用 #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款(161点数解答 | 2024-08-08 15:18:14)202
- 以下代码使用指针与结构体的作用与好处是什么? #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款 %.2f,余额不足失败", amount); } } double getbalanc(201点数解答 | 2024-08-08 15:39:09)182
- 为什么最后bankaccounttest函数中使用bankaccount account而不是bankaccount *account呢? #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款(218点数解答 | 2024-08-08 15:48:26)264
- 为什么前面deposit函数里面的printf里amount前没有&,bankacounttest函数里面printf中的acount前面有&符合? #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { print(132点数解答 | 2024-08-08 15:53:07)165