为什么printf("查询余额为%.2f", getbalance(&account)中account前面要加& #include <stdio.h> typedef struct { double balance; } bankaccount; //开户 void openaccount(bankaccount *account) { account->balance = 0; printf("开户成功"); } void deposit(bankaccount *account, double amount) { account->balance += amount; printf("存款 %.2f 成功", amount); } void withdraw(bankaccount *account, double amount) { if (account->balance >= amount) { account->balance -= amount; printf("取款 %.2f 成功", amount); } else { printf("取款 %.2f,余额不足失败"


在 `printf("查询余额为%.2f", getbalance(&account))` 中,`account` 前面加 `&` 是为了获取 `account` 变量的地址。 因为传递给 `getbalance` 函数的参数需要是一个指针(地址),这样函数才能通过这个指针来访问和修改 `account` 所指向的结构体对象中的数据。 如果不使用 `&` 取地址,传递的将是结构体对象的值,而不是其地址,这可能导致函数无法正确地操作原始的结构体对象。 [2024-08-08 15:56:21 | AI写代码神器 | 121点数解答]
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