以下是用 C 语言解决此问题的代码: ```c #include <stdio.h> #include <math.h> int main() { double a, b, c; double discriminant, root1, root2; printf("请输入 a、b、c:\n"); scanf("%lf %lf %lf", &a, &b, &c); discriminant = b * b - 4 * a * c; if (discriminant > 0) { root1 = (-b + sqrt(discriminant)) / (2 * a); root2 = (-b - sqrt(discriminant)) / (2 * a); printf("%.6lf %.6lf\n", root1, root2); } else if (discriminant == 0) { root1 = -b / (2 * a); printf("%.6lf\n", root1); } else { printf("no\n"); } return 0; } ``` [2024-09-26 00:18:01 | AI写代码神器 | 237点数解答]