// // main.cpp // step1 // // created by ljpc on 2018/8/31. // copyright © 2018年 ljpc. all rights reserved. // #include <iostream> #include <stack> #include <cstring> #include <algorithm> using namespace std; int main(int argc, const char * argv[]) { // 请在这里补充代码，完成本关任务 /********* begin *********/ stack<char> s1; stack<char> s2; char s[200]; fgets(s,200,stdin); int len=strlen(s); if(s[len-1]=='\n'){ s[len-1]='\0'; len--; } char
*p=s; while(p-s<len){ if(*p=='<'){ if(!s1.empty()){ s2.push(s1.top()); s1.pop(); } } else if(*p=='>'){ if(!s2.empty()){ s1.push(s2.top()); s2.pop(); } } else if(*p=='-'){ if(!s1.empty()){ s1.pop(); } } else { s1.push(*p); } p++; } while(!s1.empty()){ s2.push(s1.top()); s1.pop(); } string ans; while(!s2.empty()){ ans+=s2.top(); s2.pop(); } reverse(ans.begin(), ans.end()); cout<<ans<<endl; /* end */ return 0; } [2024-10-25 17:28:04 | AI写代码神器 | 518点数解答]
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- #include <iostream> #include <vector> #include <algorithm> #include <qcoreapplication> int main(int argc, char *argv[]) { qcoreapplication a(argc, argv); int minsize, maxsize, n; std::cin >> minsize >> maxsize; std::cin >> n; std::vector<int> fishsize(n); for (int i = 0; i < n; ++i) { std::cin >> fishsize[i]; } std::sort(fishsize.begin(), fishsize.end()); int safecount = 0; for (int size = minsize; size <= maxsize; ++size) { bool issaf（123点数解答 | 2024-12-01 23:56:16）135
- 快速排序：# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"（710点数解答 | 2024-11-14 10:44:25）205
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- c语言已知两个非降序链表序列s1与s2，设计函数构造出s1与s2的交集新链表s3。 1.本题中头文件引用及链表结点类型声明代码如下【此部分代码本题已经内置，无须提交】： #include<stdio.h> #include<stdbool.h> #include<stdlib.h> typedef struct node { int data; struct node *next; } node; 2.本题中main函数已经写好，代码如下【此部分代码本题已经内置，无须提交】： int main() { node *s1, *s2, *s3; //创建第1个链表 s1 = create(); //创建第2个链表 s2 = create(); //生成交集构成的新链表 s3 = getintersection(s1, s2); //释放第1个链表空间 freeall(s1); //释放第2个链表空间 freeall(s2); //输出新链表 printli（462点数解答 | 2024-12-05 22:30:36）143
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- 用两个栈实现队列#include <stdio.h>#include <stack> using namespace std; class cqueue{ public: stack<int>s1; stack<int> s2; cqueue() { void appendtail(int value){//队尾插入 int deletehead(){//队头删除 return -1; 1 int main(){ cqueue* obj= new cqueue(); obj->appendtail(1); obj->appendtail(2); obj->appendtail(3); printf("%d\n", obj->deletehead()); printf("%d\n", obj->deletehead()); printf("%d\n", obj->deletehead()); printf("%d\n", obj->deletehead()); return 0;（372点数解答 | 2024-10-17 10:43:11）150
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