stm32单片机控制8个共阳极led灯同时从中间向两边点亮
#include "stm32f10x.h" int main(void) { // Enable clock for PORTA RCC->APB2ENR |= RCC_APB2ENR_IOPAEN; // Set pins as output GPIOA->CRL |= GPIO_CRL_MODE0 | GPIO_CRL_MODE1 | GPIO_CRL_MODE2 | GPIO_CRL_MODE3 | GPIO_CRL_MODE4 | GPIO_CRL_MODE5 | GPIO_CRL_MODE6 | GPIO_CRL_MODE7; GPIOA->CRL &= ~(GPIO_CRL_CNF0 | GPIO_CRL_CNF1 | GPIO_CRL_CNF2 | GPIO_CRL_CNF3 | GPIO_CRL_CNF4 | GPIO_CRL_CNF5 | GPIO_CRL_CNF6 | GPIO_CRL_CNF7); // Initialize the LED pattern uint8_t led_pattern = 0b00011000; while (1) { // Shift the LED pattern to the right GPIOA->ODR = led_pattern; HAL_Delay(500); if (led_pattern == 0b11000000 || led_pattern == 0b00000011) { led_pattern = 0b00011000; } else { led_pattern <<= 1; } } } [2024-10-28 20:39:47 | AI写代码神器 | 565点数解答]
- 循环点亮 led 灯: (1) 使用定时器to 的方式 1,实现 8个 led 由上至下间隔 1s 流动，其中每个 led 亮 0.5s，灭0.5s，一直重复。。 (2) 使用定时器 to 的方式 1，实现 8个 led 逐个点亮，间隔 1s,一直重复。。（1193点数解答 | 2024-12-27 15:10:29）177
- 外部中断 0 由边沿触发，控制 P2 口的 8 个发光二极管依次点亮。C51 程序如下: #include <reg51.h> void ex0_isr() interrupt 0 { static unsigned char led = 0x01; P2 = led; led = (led << 1) | (led >> 7); } void main() { IT0 = 1; EX0 = 1; EA = 1; P2 = 0x01; while(1); } （228点数解答 | 2025-06-22 23:18:42）62
- #include <reg51.h> 3 sbit button=p1^0; 4 sbit led=pl^1; 5 6 bit led_state=0; 7 8日void delay(unsigned int ms){ 9 unsigned int i,j: 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 12 } 13 14日void main(){ 15 while(1){ 16 白 if (button==0){ 17 delay(20); 18 if (button-=0){ 19 while (button==ah; 20 led state=~led state; 21 led=led state; 22 } 写详细注释（697点数解答 | 2024-10-29 14:54:31）203
- #include <reg51.h> void ex0_isr() interrupt 0 { static unsigned char led = 0x01; P2 = led; led = (led << 1) | (led >> 7); } void main() { IT0 = 1; EX0 = 1; EA = 1; P2 = 0x01; while(1); }（214点数解答 | 2025-06-22 23:19:09）66
- #include <reg51.h> sbit LED = P1^0; sbit KEY = P1^1; void delay(unsigned int ms) { unsigned int i; for(; ms>0; ms--) for(i=0; i<120; i++); } void main() { while(1) { if(KEY == 0) { delay(20); if(KEY == 0) { LED = ~LED; while(KEY == 0); } } } } （326点数解答 | 2025-06-22 23:19:40）77
- #include <reg51.h> 1 2 3 sbit button=p1^0; 4 sbit led=p1^1; 5 bit led state=0; 6 7 8日void delay(unsigned int ms){ 9 unsigned int i,j; 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 1213 14 void main()【 15 while(1){ 16 if (button==0){ 17 delay(20); 18 if (button==0){ 19 1ed=0; 20 21 } 做详细注释（830点数解答 | 2024-10-29 15:29:41）197
- #include <reg51.h> 1 2 3 sbit button=p1^0; 4 sbit led=p1^1; 5 bit led state=0; 6 7 8日void delay(unsigned int ms){ 9 unsigned int i,j; 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 1213 14 void main()【 15 while(1){ 16 if (button==0){ 17 delay(20); 18 if (button==0){ 19 1ed=0; 20 21 } 做注释（693点数解答 | 2024-10-29 15:31:00）312
- #include <reg51.h> 1 2 3 sbit button=p1^0; 4 sbit led=p1^1; 5 bit led state=0; 6 7 8日void delay(unsigned int ms){ 9 unsigned int i,j; 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 1213 14 void main()【 15 while(1){ 16 if (button==0){ 17 delay(20); 18 if (button==0){ 19 1ed=0; 20 21 }（570点数解答 | 2024-10-29 15:32:29）155
- module digital_watch(clk, reset,push1,push2,push3,digit,seg,seg_2,led); input clk; input reset; input push1; input push2; input push3; output reg [5:0]digit; output reg [6:0]seg,seg_2; output reg [3:0]led; wire tmp_reset; reg tmp_second_reset; wire tmp_push1; wire tmp_push2; wire tmp_push3; wire tmp_clk_1khz; wire tmp_1sec_mux_in; wire tmp_1min_mux_in; wire tmp_1hour_mux_in; reg tmp_1sec_mux_out; reg tmp_1min_mux_out; reg tmp_1hour_mux_out; wire [2:0] sel; wire [6:0] seg1, seg2, seg3; wire（36点数解答 | 2024-11-15 10:12:43）149
- module digital_watch(clk, reset,push1,push2,push3,digit,seg,seg_2,led); input clk; input reset; input push1; input push2; input push3; output reg [5:0]digit; output reg [6:0]seg,seg_2; output reg [3:0]led; wire tmp_reset; reg tmp_second_reset; wire tmp_push1; wire tmp_push2; wire tmp_push3; wire tmp_clk_1khz; wire tmp_1sec_mux_in; wire tmp_1min_mux_in; wire tmp_1hour_mux_in; reg tmp_1sec_mux_out; reg tmp_1min_mux_out; reg tmp_1hour_mux_out; wire [2:0] sel; wire [6:0] seg1, seg2, seg3; wire（3130点数解答 | 2024-11-15 10:14:41）138
- 自动门的感应器，总共是4条线，其中两条接的是12V-24V的电源，两条是输出信号线，一个是COM口一个是NO，如果我要仿制一个，功能是检测到有人靠近门了就自动打开门，帮我用最低的价格，选满足应用的芯片和其它所需的硬件，例如esp8266、stm32，单片51、红外发射器等（586点数解答 | 2025-04-08 16:54:34）87
- 外部中断 0 由边沿触发，控制 P2 口的 8 个发光二极管依次点亮。C51 程序如下:（41点数解答 | 2025-06-22 11:25:54）78