```c #include <stdio.h> int main() { double num1, num2, result; char op; scanf("%lf %c %lf", &num1, &op, &num2); switch (op) { case '+': result = num1 + num2; break; case '-': result = num1 - num2; break; case '*': result = num1 * num2; break; case '/': if (num2 == 0) { printf("the divisor is 0.\n"); return 0; } result = num1 / num2; break; default: printf("Invalid operator!\n"); return 0; } printf("%.2lf\n", result); return 0; } ``` [2024-10-30 16:14:46 | AI写代码神器 | 209点数解答]