<!DOCTYPE html> <html lang="zh"> <head> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1.0"> <title>幸运大转盘</title> <style> body { display: flex; justify-content: center; align-items: center; height: 100vh; font-family: Arial, sans-serif; background-color: #f0f0f0; } .wheel-container { position: relative; width: 300px;
我注意到你的JavaScript代码没有完整，我来帮你完成这个幸运大转盘的功能实现，并优化一些细节： ```javascript // 完成旋转转盘函数 function spinWheel() { if (!canSpin) return; canSpin = false; spinBtn.disabled = true; // 随机旋转角度 (5-10圈 + 随机停止位置) const spinDegrees = 1800 + Math.floor(Math.random() * 1800); const sectorAngle = 360 / prizes.length; wheel.style.transform = `rotate(${spinDegrees}deg)`; // 旋转结束后确定获奖奖项 wheel.addEventListener('transitionend', function() { const actualDegrees = spinDegrees % 360; const winningIndex = Math.floor(((360 - actualDegrees) % 360) / sectorAngle); alert(`恭喜获得: ${prizes[winningIndex].text}`); canSpin = true; spinBtn.disabled = false; }, { once: true }); } // 初始化转盘 createWheel(); // 绑定按钮点击事件 spinBtn.addEventListener('click', spinWheel); ``` 优化点： 1. 添加了转盘旋转结束后的回调处理，使用`transitionend`事件监听动画结束 2. 计算实际获奖奖项，考虑了旋转圈数的模运算 3. 使用`{ once: true }`参数确保事件只触发一次 4. 重置了旋转状态和按钮状态 三条额外需要注意的逻辑点： 1. 奖项计算要考虑360度取模，确保正确对应奖项区域 2. `transitionend`事件可能会在CSS属性变化时多次触发，需要确保只处理一次 3. 旋转角度计算要包含足够多的圈数(1800度=5圈)以保证视觉效果 [2025-05-01 16:32:00 | AI写代码神器 | 389点数解答]
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