给以下代码进行注释: fn calculatevolumeandcenterofmass obj = ( local volume= 0.0 local center= [0.0, 0.0, 0.0] local biaomianji=0.0; local themesh = snapshotasmesh obj local numfaces = themesh.numfaces for i = 1 to numfaces do ( local face= getface themesh i local vert2 = getvert themesh face.z local vert1 = getvert themesh face.y local vert0 = getvert themesh face.x local dv = dot (cross (vert1 - vert0) (vert2 - vert0)) vert0 volume+= dv center+= (vert0 + vert1 + vert2) *


以下是添加注释后的代码: ```rust fn calculatevolumeandcenterofmass obj = // 定义一个名为 calculatevolumeandcenterofmass 的函数,接收一个参数 obj ( local volume = 0.0 // 定义局部变量 volume 并初始化为 0.0,用于存储体积 local center = [0.0, 0.0, 0.0] // 定义局部变量 center 并初始化为 [0.0, 0.0, 0.0],用于存储质心 local biaomianji = 0.0; // 定义局部变量 biaomianji 并初始化为 0.0 local themesh = snapshotasmesh obj // 将 obj 转换为网格并存储在 themesh 中 local numfaces = themesh.numfaces // 获取网格的面数量并存储在 numfaces 中 for i = 1 to numfaces do // 从 1 到面数量进行循环 ( local face = getface themesh i // 获取第 i 个面 local vert2 = getvert themesh face.z // 获取面中第三个顶点 local vert1 = getvert themesh face.y // 获取面中第二个顶点 local vert0 = getvert themesh face.x // 获取面中第一个顶点 local dv = dot (cross (vert1 - vert0) (vert2 - vert0)) vert0 // 进行一些向量运算 volume += dv // 将计算结果累加到体积中 center += (vert0 + vert1 + vert2) // 将顶点之和累加到质心中 ) ) ``` [2024-10-16 19:10:07 | AI写代码神器 | 378点数解答]
- 给以下代码进行注释: fn calculatevolumeandcenterofmass obj = ( local volume= 0.0 local center= [0.0, 0.0, 0.0] local biaomianji=0.0; local themesh = snapshotasmesh obj local numfaces = themesh.numfaces for i = 1 to numfaces do ( local face= getface themesh i local vert2 = getvert themesh face.z local vert1 = getvert themesh face.y local vert0 = getvert themesh face.x local dv = dot (cross (vert1 - vert0) (vert2 - vert0)) vert0 volume+= dv center+= (vert0 + vert1 + vert2) *(378点数解答 | 2024-10-16 19:10:07)167
- 用两个栈实现队列#include <stdio.h>#include <stack> using namespace std; class cqueue{ public: stack<int>s1; stack<int> s2; cqueue() { void appendtail(int value){//队尾插入 int deletehead(){//队头删除 return -1; 1 int main(){ cqueue* obj= new cqueue(); obj->appendtail(1); obj->appendtail(2); obj->appendtail(3); printf("%d\n", obj->deletehead()); printf("%d\n", obj->deletehead()); printf("%d\n", obj->deletehead()); printf("%d\n", obj->deletehead()); return 0;(372点数解答 | 2024-10-17 10:43:11)152
- 给以下代码进行注释: fn czzb a b c=(--已知三点a、b、c,求c点在ab直线上的垂足坐标 ab=b-a; ac=c-a; lab=length ab; lac=length ac; cosct=((dot ab ac)/(lab*lac));--求出cosct abxl=if cosct>=0 then ab/lab;else -1*(ab/lab)--ab的单位向量 lty=abs (lac*cosct);--求出投影长度 xl=lty*abxl;--求出偏移向量 return (a+xl);--返回垂足坐标 ) -- fn qiumianji v1 v2 v3=( -- local chang=length (v3-v1); -- local v0=czzb v1 v3 v2; -- local gao=length (v0-v2) -- local mj=0.5*chang*gao; -- return mj; -- ) fn qiumianji v1 v2 v3=( local a=length (v1-v2); local(324点数解答 | 2024-10-16 18:51:32)169
- rollout arcFilletRollout "弧形编辑器" width:300 height:150 ( local obj local activeSegment = 0 spinner spn_radius "弧线高度: " type:#float range:[-10000,10000,10] scale:0.1 button btn_apply "应用修改" width:100 height:30 on spn_radius changed val do ( if activeSegment == 0 do return undo "Adjust Arc" on ( try ( -- 增强对象验证 if not (isValidNode obj) do throw "对象无效或已被删除" if classOf obj != Editable_Spline do t(656点数解答 | 2025-02-24 21:43:38)111
- 给以下代码进行注释: for i=0 to selection.count do ( if i!=0 then ( if superclassof selection[i]==geometryclass do ( tomesh = snapshotasmesh selection[i]; if tomesh.numverts!=0 then ( sz=calculatevolumeandcenterofmass selection[i]; for j=1 to cdsz.count do ( xlc = xlx.application.cells (i+1) j; cdsy=finditem quansz cdsz[j];--菜单索引 xlc.value=sz[cdsy]; ) ) ) ) else( for j=1 to cdsz.count do ( xlc = xlx.application(386点数解答 | 2024-10-16 19:29:32)170
- 给以下代码进行注释: for i=0 to selection.count do ( if i!=0 then ( if superclassof selection[i]==geometryclass do ( tomesh = snapshotasmesh selection[i]; if tomesh.numverts!=0 then ( sz=calculatevolumeandcenterofmass selection[i]; for j=1 to cdsz.count do ( xlc = xlx.application.cells (i+1) j; cdsy=finditem quansz cdsz[j];--菜单索引 xlc.value=sz[cdsy]; ) ) ) ) else( for j=1 to cdsz.count do ( xlc = xlx.application(698点数解答 | 2024-10-16 19:33:34)201
- const dfiles = dv.pages(`"文件目录"`), yamlkey = 'source' , dc = (str, obj)=> object.assign(document.createelement(str), obj||{}) const inpu = dc('input', { style: 'width: 120px;', /*输入框宽度*/ onchange: ()=> arr.includes(inpu.value) && xl(), }) inpu.setattribute('list', 'demo') const sele = dc('datalist', {id: 'demo'}) const arr = array.from(new set(dfiles.map(p=> p[yamlkey]).filter(p=> p))) arr.unshift('..'); arr.map(p=> sele.append(dc('option', {value: p}))) dv.container.append(inpu, sele) const(139点数解答 | 2024-11-22 23:56:54)158
- const dfiles = dv.pages(`"文件目录"`), yamlkey = 'source' , dc = (str, obj)=> object.assign(document.createelement(str), obj||{}) const inpu = dc('input', { style: 'width: 120px;', /*输入框宽度*/ onchange: ()=> arr.includes(inpu.value) && xl(), }) inpu.setattribute('list', 'demo') const sele = dc('datalist', {id: 'demo'}) const arr = array.from(new set(dfiles.map(p=> p[yamlkey]).filter(p=> p))) arr.unshift('..'); arr.map(p=> sele.append(dc('option', {value: p}))) dv.container.append(inpu, sele) const(630点数解答 | 2024-11-23 00:01:37)123
- objects = selection as array if objects.count == 0 then ( messagebox "请先选择一个或多个模型" title:"错误" ) -- 创建CSV文件 csvPath = "C:\\sers\\ASUS\\Desktop" csvFile = createfile csvPath if (csvFile == undefined) do ( messagebox "无法创建CSV文件" title:"错误" ) -- 导出模型长度数据 format "Name,Length\n" to:csvFile for obj in objects do ( objName = obj.name objLength = obj.max format "%,%\n" objName objLength to:csvFile ) -- 导出成功提示 format "模型长度已成功导出到CSV文件:%.\n" csvPath messagebox "模型长度已成功(525点数解答 | 2025-07-09 15:37:45)66
- 题目内容: 编写程序,求斐波那契数列第n项的值,其中f0=1,f1=1,fn=fn-1+fn-2。 输入格式: 一个整数n,n≥0 输出格式: 斐波拉契数列中索引值为n的项 输入样例: 6 输出样例: 13 时间限制:500ms内存限制:32000kb(251点数解答 | 2024-11-14 16:10:12)131
- 写出enter your name. alice hello alice, do you want to repeat this program? yes enter your name. bob hello bob, do you want to repeat this program? yes enter your name. charlie hello charlie, do you want to repeat this program? no goodbye, charlie! 的c++代码(267点数解答 | 2024-10-22 08:36:28)151
- 给以下代码进行注释: fn qiumianji v1 v2 v3=( local a=length (v1-v2); local b=length (v2-v3); local c=length (v1-v3); local p=0.5*(a+b+c); local s=sqrt (p*(p-a)*(p-b)*(p-c)); return s; )(224点数解答 | 2024-10-16 18:56:35)149