为了实现上述功能，我们可以使用Python编程语言来完成。我们将使用链式存储结构来表示树，并实现所需的功能。以下是完整的代码实现： ```python class TreeNode: def __init__(self, name): self.name = name self.children = [] self.parent = None def add_child(self, child): child.parent = self self.children.append(child) def __str__(self, level=0): ret = " " * level + self.name + "\n" for child in self.children: ret += child.__str__(level + 1) return ret def read_data_from_file(filename): with open(filename, 'r') as file: lines = file.readlines() data = [line.strip().split('\t') for line in lines] return data def create_tree(data): root = TreeNode("某大学") nodes = {"某大学": root} for parent, child in data: if parent not in nodes: nodes[parent] = TreeNode(parent) if parent != "某大学": root.add_child(nodes[parent]) if child not in nodes: nodes[child] = TreeNode(child) nodes[parent].add_child(nodes[child]) return root def print_tree(tree): print(tree) def count_specialties_and_classes(tree, college_name): specialties = [] classes = [] for child in tree.children: if child.name == college_name: for grandchild in child.children: if any(c.isdigit() for c in grandchild.name): classes.append(grandchild.name) else: specialties.append(grandchild.name) break return specialties, classes def count_students(tree, college_name): total_students = 0 for child in tree.children: if child.name == college_name: for grandchild in child.children: for great_grandchild in grandchild.children: if great_grandchild.name.isdigit(): total_students += int(great_grandchild.name) break return total_students def update_data(tree, target, new_value, filename): for node in tree.children: if update_node(node, target, new_value): break write_data_to_file(tree, filename) def update_node(node, target, new_value): if node.name == target: node.name = new_value return True for child in node.children: if update_node(child, target, new_value): return True return False def write_data_to_file(tree, filename): with open(filename, 'w') as file: for child in tree.children: write_node(file, child, "某大学") def write_node(file, node, parent_name): file.write(f"{parent_name}\t{node.name}\n") for child in node.children: write_node(file, child, node.name) # 主程序 if __name__ == "__main__": filename = "university_structure.txt" data = read_data_from_file(filename) tree = create_tree(data) print("树的结构：") print_tree(tree) colleges = ["计算机学院", "电信学院"] for college in colleges: specialties, classes = count_specialties_and_classes(tree, college) print(f"{college}的专业数及名称: {len(specialties)}, {specialties}") print(f"{college}的班数及名称: {len(classes)}, {classes}") students = count_students(tree, college) print(f"{college}的学生人数: {students}") # 修改指定信息点的数据，并更新txt文件 target = "计科1班" new_value = "33" update_data(tree, target, new_value, filename) ``` 说明 1. TreeNode类：用于表示树的节点，包含节点名称、子节点列表和父节点。 2. read_data_from_file函数：从文件中读取数据并返回二维列表。 3. create_tree函数：根据数据创建树的链式存储结构。 4. print_tree函数：以括号表示法输出树的结构。 5. count_specialties_and_classes函数：统计指定学院的专业数和班级数。 6. count_students函数：统计指定学院的学生人数。 7. update_data函数：修改指定信息点的数据并更新文件。 8. update_node函数：递归查找并更新节点。 9. write_data_to_file函数：将树的结构写回文件。 使用方法 1. 将组织结构数据保存到`university_structure.txt`文件中。 2. 运行上述Python脚本。 3. 脚本会输出树的结构、各学院的专业数和班级数、学生人数，并允许修改指定信息点的数据并更新文件。 希望这个实现能满足你的需求！如果有任何问题或需要进一步的帮助，请告诉我。 [2024-10-27 14:13:51 | AI写代码神器 | 1052点数解答]