from crypto.util.number import * from secret import flag m = bytes_to_long(flag) p = 10453494189896814393489082401798067658149446733396819562864863864546212967979882859223572465368952108706223229855398759198028181181112373274325597469810991 g = 9232525983054729206798795323103994881466871254409162769478260108293334381919547345560776320223556367674557075231517532178126540033249822348773494136177921 c = 0 for i in range(m): c = (c + g) % p print(f'{c = }') 阅读加密逻辑


The provided Python code appears to implement a cryptographic operation, most likely involving a basic form of public-key or threshold cryptography. Here's a breakdown of the code: 1. Imports: ```python from crypto.util.number import * from secret import flag ``` This line imports utility functions for working with numbers, as well as a secret variable named `flag`. The content of `flag` is kept secret, likely containing sensitive information or a password. 2. Converting `flag` to a number: ```python m = bytes_to_long(flag) ``` This line converts the `flag` from bytes (a string of bytes) to a long integer. The `bytes_to_long` function is not shown but typically converts a bytes-like object into its numeric representation. 3. Parameters: ```python p = 10453494189896814393489082401798067658149446733396819562864863864546212967979882859223572465368952108706223229855398759198028181181112373274325597469810991 g = 9232525983054729206798795323103994881466871254409162769478260108293334381919547345560776320223556367674557075231517532178126540033249822348773494136177921 c = 0 ``` Here, `p` is a large prime number and `g` is a generator, which are commonly used in cryptographic protocols (e.g., Diffie-Hellman). The variable `c` is initialized to zero; it is later used to accumulate a value. 4. The Loop: ```python for i in range(m): c = (c + g) % p ``` This loop runs `m` times, where `m` is the numeric value of the `flag`. In each iteration, it adds the value of `g` to `c` and then takes the result modulo `p`. This effectively calculates `c` as: \[ c = (g \times m) \mod p \] since adding `g` multiple times is equivalent to multiplying `g` by `m` in modular arithmetic. 5. Output: ```python print(f'{c = }') ``` Finally, the value of `c` is printed out in a formatted string. Summary of the Cryptographic Logic: - This code effectively computes a value `c` which can be interpreted as an encrypted or transformed representation of the `flag`. - It's accumulating the value of a generator `g` for a number of times defined by the numeric representation of the secret `flag`, modulo a prime number `p`. - This pattern could be part of a scheme for revealing or hiding the secret based on mathematical properties of modular arithmetic, possibly related to public key encryption. Security Implications: - If someone were to analyze `c`, they could attempt to deduce `m` (which is derived from the `flag`), but they would require knowledge of `g` and `p`. - Without these parameters and without access to the flag itself, reversing the operation to reveal sensitive data would be computationally infeasible, assuming secure element parameters. [2024-11-02 16:13:24 | AI写代码神器 | 1878点数解答]
- from crypto.util.number import * from secret import flag m = bytes_to_long(flag) p = 10453494189896814393489082401798067658149446733396819562864863864546212967979882859223572465368952108706223229855398759198028181181112373274325597469810991 g = 9232525983054729206798795323103994881466871254409162769478260108293334381919547345560776320223556367674557075231517532178126540033249822348773494136177921 c = 0 for i in range(m): c = (c + g) % p print(f'{c = }') 阅读加密逻辑(1878点数解答 | 2024-11-02 16:13:24)65
- import javax.swing.*; import java.awt.*; import java.awt.datatransfer.clipboard; import java.awt.datatransfer.stringselection; import java.awt.datatransfer.transferable; import java.awt.event.*; import java.io.*; import java.nio.file.files; import java.nio.file.path; import java.nio.file.paths; import java.time.localdatetime; import java.util.hashmap; import java.util.list; import java.util.map; import java.util.random; public class copy { static private final jtextarea textarea = new jtext(1497点数解答 | 2024-08-25 09:40:33)297
- import openpyxl import smtplib import imaplib import email import json import os import re from bs4 import BeautifulSoup from fastapi import FastAPI, Form from openpyxl.styles import Alignment from email.mime.multipart import MIMEMultipart from email.mime.base import MIMEBase from email.header import decode_header from email import encoders import pandas as pd app = FastAPI() RECEIVER_EMAILS = { 0: "yundongshijie001@protonmail.com", 1: "xiaobudian001@protonmail.com" } email_address = "(182点数解答 | 2025-04-12 00:49:09)142
- package com.example.weather; import android.content.context; import android.media.mediaplayer; import android.net.uri; import android.os.bundle; import android.util.log; import android.view.layoutinflater; import android.view.view; import android.view.viewgroup; import android.webkit.websettings; import android.webkit.webview; import android.webkit.webviewclient; import android.widget.videoview; import androidx.fragment.app.fragment; public class realtimemonitoringfragment extends fragment {(30点数解答 | 2024-10-12 10:31:18)199
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- from kivy.app import app from kivy.uix.button import button from kivy.uix.boxlayout import boxlayout from kivy.uix.filechooser import filechooserlistview from kivy.uix.popup import popup from kivy.uix.label import label from kivy.uix.screenmanager import screenmanager, screen from kivy.core.window import window from kivy.uix.treeview import treeview, treeviewlabel from unitypy import assetsmanager from unitypy.exceptions import unitypyerror import os from pil import image import time class file(262点数解答 | 2024-12-01 17:07:07)195
- import os import datetime from flask import Flask, request, jsonify import requests from flask_cors import CORS import re import matplotlib matplotlib.use('Agg') import matplotlib.pyplot as plt import numpy as np import base64 from io import BytesIO import pandas as pd import traceback # 添加traceback以获取详细错误信息 plt.rcParams["font.sans-serif"] = ["SimHei"] app = Flask(__name__) CORS(app) FASTGPT_API_URL = 'http://localhost:3000/api/v1/chat/completions' FASTGPT_API_KEY = 'fastgpt-gWzitHpBa8XRr0q(713点数解答 | 2025-06-18 16:00:34)92
- 如何用aide编写的xposed软件拦截一个smail类里面的方法名,请参考如下代码进行修改达到效果 import android.content.*; import android.graphics.*; import android.os.*; import android.widget.*; import de.robv.android.xposed.*; import de.robv.android.xposed.callbacks.*; import java.util.*; import android.app.*; /* 注意:该类不要自己写构造方法,否者可能会hook不成功 * 开发xposed模块完成以后,关闭bebug以提升性能 * debug模式只需要第一次重启,以后修改hook代码就不用重启了 */ public class xposed implements ixposedhookloadpackage { public static activity 上下文; @override public void handleloadpackage(x(649点数解答 | 2024-10-12 00:15:48)195
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- # 在线聊天程序服务器端 import tkinter import tkinter.font as tkfont import socket import threading import time import sys class serverui(): local = '127.0.0.1' port = 5505 global serversock flag=false def __init__(self): self.root = tkinter.tk() self.root.title('python在线聊天-服务器端v1.0') self.frame = [tkinter.frame() for _ in range(4)] self.chattextscrollbar = tkinter.scrollbar(self.frame[0]) self.chattextscrollbar.pack(side=tkinter.right,(1152点数解答 | 2024-11-11 21:24:15)134
- import numpy as np import matplotlib.pyplot as plt from scipy.stats import chi2 import pandas as pd import itertools from statsmodels.stats.outliers_influence import variance_inflation_factor from sklearn.impute import SimpleImputer # 用于简单缺失值填充 import plotly.graph_objects as go from plotly.subplots import make_subplots plt.rcParams['font.sans-serif'] = ['SimHei'] # 用来正常显示中文标签 plt.rcParams['axes.unicode_minus'] = False # 用来正常显示负号 # 问题背景与意义说明 # 在生产过程中,产品可能会出现多种类型的缺陷,通过对不同缺陷类型的频数分布进行监控, # 可以及时发(925点数解答 | 2025-04-05 17:47:55)111
- 本题要求编写程序,计算交错序列 1-2/3+3/5-4/7+5/9-6/11+... 的前n项之和。 输入格式: 输入在一行中给出一个正整数n。 输出格式: 在一行中输出部分和的值,结果保留三位小数。 #include<stdio.h> int main() { int n,i,flag=1; double sum=0,t=0; scanf("%d",&n); for(i=1;i<=n;i++){ t=flag*1.00*i*1.0/(2i-1); sum=sum+t; flag=-flag; } printf("%.3lf",sum); return 0; } 这段代码错哪了(206点数解答 | 2024-11-13 20:17:31)117