用c语言编程求sum = 1 + 1/2 + 1/3 + 1/4 + ... + 1/n的值,输出结果小数点后保留6位有效数字。(1<=n<=100) 输入格式: "%d" 输入格式: "sum=%.6f" 0 题目列表 c 8910111213141516176734512 scanf("%d", &n);for (int i = 1; i <= n; i++) {sum += 1.0 / i;}printf("sum=%.6f\n", sum);return 0;}printf("请输入 n 的值(1 <= n <= 100):");int main() {int n;double sum = 0;#include <stdio.h>


以下是修正后的 C 语言代码: ```c #include <stdio.h> int main() { int n; double sum = 0; printf("请输入 n 的值(1 <= n <= 100):"); scanf("%d", &n); for (int i = 1; i <= n; i++) { sum += 1.0 / i; } printf("sum=%.6f\n", sum); return 0; } ``` [2024-10-16 14:35:50 | AI写代码神器 | 120点数解答]
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