以下是使用C++编写的解决方案: ```cpp #include <iostream> #include <iomanip> double calculateSalary(double sales) { double basicSalary = 1000.00; double commission = 0.00; double totalSalary = 0.00; if (sales <= 10000) { totalSalary = basicSalary; } else if (sales <= 20000) { commission = (sales - 10000) * 0.05; totalSalary = basicSalary + commission; } else if (sales <= 50000) { commission = 10000 * 0.05 + (sales - 20000) * 0.06; totalSalary = basicSalary + commission; } else if (sales <= 100000) { commission = 10000 * 0.05 + 30000 * 0.06 + (sales - 50000) * 0.07; totalSalary = basicSalary + commission; } else { commission = 10000 * 0.05 + 30000 * 0.06 + 50000 * 0.07 + (sales - 100000) * 0.08; totalSalary = basicSalary + commission; } return totalSalary; } int main() { double sales; std::cout << "请输入销售额:"; std::cin >> sales; double salary = calculateSalary(sales); std::cout << "应发工资额为:" << std::fixed << std::setprecision(2) << salary << "元" << std::endl; return 0; } ``` 在该解决方案中,首先定义了基本工资和提成变量。然后根据不同的销售额范围,计算相应的提成金额。最后将基本工资和提成相加,得到应发的工资额,并通过std::fixed和std::setprecision(2)控制输出保留两位小数。 注意:如果使用DevC++编译器,可能需要包含头文件 `#include <iomanip>` 来使用 `std::setprecision()` 函数。 [2024-11-21 00:22:29 | AI写代码神器 | 976点数解答]