在文本框内输入内容,点击“问AI”即可获得参考结果


"酷代码AI"是一家去中心化AI发财平台,旨在共享AI低成本地处理文案类、代码类的工作,提升学习、工作的效率与质量。一次注册,畅游多家AI产品!
最新免费问AI
- 数据结构c++进出栈进制转换二进制转八进制转十进制转十六进制(1014点数解答 | 2024-10-16 20:05:31)71
- 数据结构c++进出栈进制转换(734点数解答 | 2024-10-16 20:03:47)99
- 数据结构进制转换二进制转八进制转十进制转十六进制(641点数解答 | 2024-10-16 20:01:15)60
- c++用栈的知识写进制转换(595点数解答 | 2024-10-16 19:51:34)58
- 用栈写二进制转八进制转十进制转十六进制(1526点数解答 | 2024-10-16 19:49:50)81
- 给以下代码进行注释: for i=0 to selection.count do ( if i!=0 then ( if superclassof selection[i]==geometryclass do ( tomesh = snapshotasmesh selection[i]; if tomesh.numverts!=0 then ( sz=calculatevolumeandcenterofmass selection[i]; for j=1 to cdsz.count do ( xlc = xlx.application.cells (i+1) j; cdsy=finditem quansz cdsz[j];--菜单索引 xlc.value=sz[cdsy]; ) ) ) ) else( for j=1 to cdsz.count do ( xlc = xlx.application(698点数解答 | 2024-10-16 19:33:34)198
- 给以下代码进行注释: for i=0 to selection.count do ( if i!=0 then ( if superclassof selection[i]==geometryclass do ( tomesh = snapshotasmesh selection[i]; if tomesh.numverts!=0 then ( sz=calculatevolumeandcenterofmass selection[i]; for j=1 to cdsz.count do ( xlc = xlx.application.cells (i+1) j; cdsy=finditem quansz cdsz[j];--菜单索引 xlc.value=sz[cdsy]; ) ) ) ) else( for j=1 to cdsz.count do ( xlc = xlx.application(386点数解答 | 2024-10-16 19:29:32)168
- 用java写出,(38点数解答 | 2024-10-16 19:21:02)85
- 给以下代码进行注释: fn calculatevolumeandcenterofmass obj = ( local volume= 0.0 local center= [0.0, 0.0, 0.0] local biaomianji=0.0; local themesh = snapshotasmesh obj local numfaces = themesh.numfaces for i = 1 to numfaces do ( local face= getface themesh i local vert2 = getvert themesh face.z local vert1 = getvert themesh face.y local vert0 = getvert themesh face.x local dv = dot (cross (vert1 - vert0) (vert2 - vert0)) vert0 volume+= dv center+= (vert0 + vert1 + vert2) *(378点数解答 | 2024-10-16 19:10:07)164
- 给以下代码进行注释: fn qiumianji v1 v2 v3=( local a=length (v1-v2); local b=length (v2-v3); local c=length (v1-v3); local p=0.5*(a+b+c); local s=sqrt (p*(p-a)*(p-b)*(p-c)); return s; )(224点数解答 | 2024-10-16 18:56:35)147
- 给以下代码进行注释: fn czzb a b c=(--已知三点a、b、c,求c点在ab直线上的垂足坐标 ab=b-a; ac=c-a; lab=length ab; lac=length ac; cosct=((dot ab ac)/(lab*lac));--求出cosct abxl=if cosct>=0 then ab/lab;else -1*(ab/lab)--ab的单位向量 lty=abs (lac*cosct);--求出投影长度 xl=lty*abxl;--求出偏移向量 return (a+xl);--返回垂足坐标 ) -- fn qiumianji v1 v2 v3=( -- local chang=length (v3-v1); -- local v0=czzb v1 v3 v2; -- local gao=length (v0-v2) -- local mj=0.5*chang*gao; -- return mj; -- ) fn qiumianji v1 v2 v3=( local a=length (v1-v2); local(324点数解答 | 2024-10-16 18:51:32)167
- 给以下代码进行注释: fn jiequzm str=(--截取字符串中的字母 local zdsy; num=str.count; for i =num to 1 by -1 do ( if str[i]>="a" and str[i]<="z" then zdsy=i; ) if zdsy!=undefined then ( return (substring str 1 (zdsy+1)); ) else( return undefined; ) )(224点数解答 | 2024-10-16 18:48:21)201